Sizing a propeller to match an electric motor

Discussion in 'Electric Propulsion' started by ziper1221, Jan 6, 2025.

  1. Heimfried
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    Heimfried Senior Member

    This article will be part of an old publication (Transactions (?) 1952) from RINA.
    Try to contact them:

    Publications Enquiry
    publications@rina.org.uk
    t: +44 (0)20 7235 4622

    The Royal Institution of Naval Architects
    8-9 Northumberland Street, London, WC2N 5DA, UK
     
  2. ziper1221
    Joined: May 2018
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    ziper1221 Junior Member

    Ok, I think I did the math properly. I finally tracked down a paper (Thank you Heimfried) by Newton and Rader who describe a series of propellers. I started with the 3 blade, 48% blade area ratio, 2.08 pitch to diameter ratio. I determined that my 5kw motor would put out about 20 newton meters of torque at the wheel after losses. I had initially planned on a propeller of .24 meter diameter and a maximum RPS of 41.67. However, at peak efficiency at a J of 1.8, this would require nearly 30 kW of power input. Obviously this is unrealistic. I see four options:

    1. Keep the propeller same as above, and just operate at very low slips. (I think this was my subconscious plan before doing the math.) This would result is pathetic efficiencies -- a J of 2.25, the highest with data -- would require a torque input of 31.7 Nm for a mere 107.5 N of thrust. This wouldn't work unless vessel drag was unrealistically low.
    2. Reduce the propeller diameter and increase the RPS, but maintain the pitch ratio. This looks like it would work quite well -- if my lower unit just doesn't blow up, which I have not much faith in!
    3. Maintain the same RPS, reduce the diameter, and increase the pitch ratio: This seems like it would be the best option, but I can't find any data on P/D ratios higher than 2 -- despite the fact that the highest ratio almost universally has the highest efficiency!
    4. Reduce the pitch: Dropping down to 1.68 P/D actually doesn't really help me much. The speed loss is just too great compared to the other options.

    So, I guess I need to get a better idea of what my vessel drag curve will look like, and then I can tweak the propeller dimensions to intersect it at a reasonable efficiency while maximizing speed.

    Some questions I still have:
    • Does Kt account for friction and other losses at the wheel? (I assume yes)
    • How do I estimate my t and w? I have found some information in the literature about w, but it is all centered around displacement vessels. I have not yet turned up anything empirical about outboard legs or hydrofoils or flat bottomed planing vessels, and I am hesitant to use a purely theoretical method.
     
  3. ziper1221
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    ziper1221 Junior Member

    I decided to go with a compromise, 16x33.3 cm turning at a 50% overspeed. Here are the plots for torque and thrust. The J values 1.5 and 2.05 correspond to the upper and lower 70% efficiency, while 1.8 is peak 78% efficiency.
    power reqs 16cm.png thrust 16cm.png
    However, I ran into more issues when it came time to model the propeller. I transcribed the offsets given in the paper, but when I plotted them there was a strange result. The authors had modified the original sections to reduce cavitation by removing part of the leading edge and pressure face, but my plots make it look like they had actually moved parts of the section, which I'm pretty sure is incorrect. All I did was scale the table of offsets by desired fraction of the nominal size. I'm not sure if I did something wrong here, or if this issue is somehow innate to the chord line and thickness presentation of the sections.
    nr truncation.PNG
    nr sections.PNG
    funky section.PNG
    table of offsets.PNG

    Also, I don't understand if these sections are supposed to be on flat planes or cylindrical. The wrong assumption could result in too much or too little blade area, especially in the tips. The paper doesn't mention, would they have expected readers to know based on the methods in use at the time?

    Thank you in advance to @jehardiman or anyone else who may be able to point me in the right direction.
     
  4. jehardiman
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    jehardiman Senior Member

    *****
    3rd Edit: Ignore this cut section

    *****
    Edit to add: Check the paper again, as I am not sure that delta, Yt and Yc non-dimensionalized...i.e. the table values are for a real 5" radius propeller.

    2nd Edit: I'm plotting this out...hold on a few.
     
    Last edited: Mar 13, 2025
  5. jehardiman
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    jehardiman Senior Member

    Ok, I plotted it out, assuming the data given is inches for a 5"R wheel. Yes, there is a reverse, but only on the 0.3R section, and it is not as bad as you show. What I think they did is something I also have done at the root where there is a large difference between angle of attack and geometric pitch angle. They twisted the LE into the flow to gain pressure and prevent immediate separation.
    upload_2025-3-13_13-31-36.png
     
  6. ziper1221
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    ziper1221 Junior Member

    Not saying I don't believe you, but I don't understand. Wouldn't this cause seperation at practically any positive aoa?
     
  7. jehardiman
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    jehardiman Senior Member

    No, there are different effects playing off against each other here. First is the fact that we are dealing with the root. See the figure below.
    upload_2025-3-13_16-42-19.png
    The geometric pitch is fixed. However the actual pitch varies with omega*r and Va. Because r is so small near the root, to achieve large Va either the Geometric pitch, and therefore the hub, must become large or alpha goes negative. When alpha goes negative...
    [​IMG]
    ...pressure is built up on the suction face LE and the pressure face goes into negative pressure, losing all thrust development as effectively as if you backed the wheel. To prevent this you twist just the LE into the relative velocity, Vr, always maintaining a pressure on the pressure face.
    OK you say, then why don't you just increase omega?...Because then the tip, which at large r, would be moving very fast. This has bigger issues because general cavitation is a function of Vr^2. Considering that Vr at the tip is 3.33 times Vr at the root, and that thrust per unit area is also proportional to Vr^2, it is better to make the root a slightly less efficient lifting surface than cavitating the tip. This is why most blades are widest at ~0.7r, because you also have to play with the tip to prevent the AoA from becoming too large.

    Really, there are whole courses on propeller design about these topics.
     
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  8. jehardiman
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    jehardiman Senior Member

    I noticed I didn't answer this part of the question. Think about the sections being laid out flat on a strip of paper 2*pi*r wide and geometric pitch high. The line from a lower corner to the opposite upper corner is the cord line for development (which corner depends on whether it is RH or LH wheel). From this and geometry you can lay out the 3D shape. Note that Pitch does not have to be, and usually isn't, constant across the radius; usually it is reduced at the root (due to the wake fraction) and tip (due to large omega r) for reasons mentioned in my previous posts.
    [​IMG]
     
  9. Lee Eldridge
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    Lee Eldridge Junior Member

    Arggg!!! I have been searching for weeks looking for data on props. Everyone talks about horsepower and that is just doing stuff backwards when you have a system that creates clean gobs of torque. I have a really good idea of the Hull resistance and will confirm it with in water tests (about 25kgF at 5 knots). Maximum speed I will get to under motor is about 5 knots as hull speed is rated at 6.5 knots. Flat bottomed Norwalk Island Sharpie 8m with gross weight of about 2000kg. I will most only motor in and out of the berth and through narrow, shallow channels otherwise sail is the way I sail. If I cannot sail there I will stop and make a cup of tea and think about what to do. I am going to use an off the shelf prop and outboard motor bottom end and mount the outboard on the tiller box and it appears Yamaha motors have the greatest range of props. Again at 5 knots max, the largest prop the motor can turn will be close to the most efficient at the prop end. A tool I found suggest for a 10 itch prop I need about a pitch of 6 itches with a rotational speed of around 1000RPM. Another tool I found suggested that this might give a thrust of about 50kgF (~500N). That gives me an acceleration from zero to 5 knots under 20 seconds - really nice (I like slow). Now how do I find drive shaft torque prop data sheets never list thrust let alone shaft torque required ? Electric motors link amperes and torque as the primary relationships. Power is just a derived quantity based on usage. Once I know torque and RPM everything else is selectable. I have a wide range of motors available, some even with inbuilt reductions above the 2:1 typical of the outboard lower unit. It seems the electric bike people have determined that voltages between 72 and 96v provide optimum motor performance but my guess is I cab even wire a 48v system to work. I bought Gerrs book and it is completely irrelevant to my story. Ditto the Nicolsons.
     
  10. Lee Eldridge
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    Lee Eldridge Junior Member

    Lee: I am doing the electric route conversion of my sharpie sailboat. Am an experienced EE and am confounded with the situation. Never ever need power ratings. Guidelines (Gear) are biggest prop you can spin with the least pitch to just give desired speed. Gerr lists a 1 itch increase in diameter being equal to a 3 itch pitch increase. S0 design prop first to discover pitch to get speed desired (for me it is on the low side - maybe 5, 6, 7 maybe 8 itches depending on RPM). Then from boat resistance determine needed thrust and that sets prop diameter and to some extent number of blades. Again Gerr suggests that for low speed rotation prop a 4 blade is better. Yamaha have three and four blade props from 7 to nearly 10 itches and pitches from 5 to more than 12. Many motors specify peak torque at some RPM - and I assume that is the RPM that torque drops off. So locating a motor with torque for maximum speed is first guess. Then selecting a motor with appropriate current and voltage and RPM and how to mount it. Then select batteries for desired run time. Assume select motor with more torque than minimum so there is some headroom for error. I do not need much more torque with a hull speed of 6.5 knots. BTW it is important to have forward and reverse about the same in a sailboat, so that might be another prop restriction. Currently I have estimated the maximum forces to be around 50kgF so that is very manageable using relatively crude designs. The Tohatsu outboard currently destined for sale weighs in around 45kg.
     
  11. Lee Eldridge
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    Lee Eldridge Junior Member

    This is a BLDC torque curve. [​IMG]
     
  12. gonzo
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    gonzo Senior Member

    Horsepower and Torque are two different units of measure. Horsepower is Torque multiplied by radial velocity (RPM or other units). It is not backwards at all to talk about power. Torque at very low radial velocity may not have the power to even move a boat.
     

  13. gonzo
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    gonzo Senior Member

    Compare that graph to that of the propeller and the resistance of the boat.
     
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